-14w^2+7w=0

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Solution for -14w^2+7w=0 equation: 



-14w^2+7w=0

a = -14; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-14)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$


$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-14}=\frac{-14}{-28}
=1/2
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-14}=\frac{0}{-28}
=0
$

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